tags probability
2023PB_HW6.pdf
p=122P(x=3)=Cx6×px×(1−p)6−x=0.0535
p=0.45P(x)=Cx10×px×(1−p)10−xwhen x=4 the P(x) have maximum probability 0.2383
p=0.999P(x)=Cx8×p8−x×(1−p)xP(x={2,4,6,8})=0.0000278324891609
p=0.025,E(x)=p∗80,λ=E(x)P(x)=x!e−λ×λxP(X>=2)=1−P(0)−P(1)=0.59399415029
p=103,E(x)=p∗35,λ=E(X)P(x)=x!e−λ×λxP(x=10)=0.1236P(x=10)2=0.015278
P(x)=x!e−λ×λxP(x=1)=1!e−λ×λ1P(x=3)=3!e−λ×λ3P(x=1)P(x=3)=3!λ2=1λ=2.4494P(x=5)=0.0634449
p=0.2P(x,r)=Cr−1x−1×(1−p)x−r×prP(8,3)=0.05505
P(x)=px−1∗(1−p)P(x≥n)=1−i=1∑n−1P(i)
p=0.15P(x)=C10−1x+10−1×p10×(1−p)x
p=n50,X∼Hgeo(n,50,50)d=50,t=50P(x)=CtnCxdCt−xn−dPn=625(x=4)Pn=624(x=4)≤1,Pn=625(x=4)Pn=626(x=4)≤1n=625